(**************************************************************************) (* *) (* Copyright (C) Jean-Christophe Filliatre *) (* *) (* This software is free software; you can redistribute it and/or *) (* modify it under the terms of the GNU Library General Public *) (* License version 2.1, with the special exception on linking *) (* described in file LICENSE. *) (* *) (* This software is distributed in the hope that it will be useful, *) (* but WITHOUT ANY WARRANTY; without even the implied warranty of *) (* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. *) (* *) (**************************************************************************) (*s Heaps *) module type Ordered = sig type t val compare : t -> t -> int end exception EmptyHeap (*s Imperative implementation *) module Imperative(X : Ordered) = struct (* The heap is encoded in the array [data], where elements are stored from [0] to [size - 1]. From an element stored at [i], the left (resp. right) subtree, if any, is rooted at [2*i+1] (resp. [2*i+2]). *) type t = { mutable size : int; mutable data : X.t array } (* When [create n] is called, we cannot allocate the array, since there is no known value of type [X.t]; we'll wait for the first addition to do it, and we remember this situation with a negative size. *) let create n = if n <= 0 then invalid_arg "create"; { size = -n; data = [||] } let is_empty h = h.size <= 0 (* [resize] doubles the size of [data] *) let resize h = let n = h.size in assert (n > 0); let n' = 2 * n in let d = h.data in let d' = Array.create n' d.(0) in Array.blit d 0 d' 0 n; h.data <- d' let add h x = (* first addition: we allocate the array *) if h.size < 0 then begin h.data <- Array.create (- h.size) x; h.size <- 0 end; let n = h.size in (* resizing if needed *) if n == Array.length h.data then resize h; let d = h.data in (* moving [x] up in the heap *) let rec moveup i = let fi = (i - 1) / 2 in if i > 0 && X.compare d.(fi) x < 0 then begin d.(i) <- d.(fi); moveup fi end else d.(i) <- x in moveup n; h.size <- n + 1 let maximum h = if h.size <= 0 then raise EmptyHeap; h.data.(0) let remove h = if h.size <= 0 then raise EmptyHeap; let n = h.size - 1 in h.size <- n; let d = h.data in let x = d.(n) in (* moving [x] down in the heap *) let rec movedown i = let j = 2 * i + 1 in if j < n then let j = let j' = j + 1 in if j' < n && X.compare d.(j') d.(j) > 0 then j' else j in if X.compare d.(j) x > 0 then begin d.(i) <- d.(j); movedown j end else d.(i) <- x else d.(i) <- x in movedown 0 let pop_maximum h = let m = maximum h in remove h; m let iter f h = let d = h.data in for i = 0 to h.size - 1 do f d.(i) done let fold f h x0 = let n = h.size in let d = h.data in let rec foldrec x i = if i >= n then x else foldrec (f d.(i) x) (succ i) in foldrec x0 0 end (*s Persistent implementation *) module type PersistentSig = sig type elt type t val empty : t val add : elt -> t -> t val maximum : t -> elt val remove : t -> t val iter : (elt -> unit) -> t -> unit val fold : (elt -> 'a -> 'a) -> t -> 'a -> 'a end module Persistent(X : Ordered) = struct (* Heaps are encoded as complete binary trees, i.e., binary trees which are full expect, may be, on the bottom level. These trees also enjoy the heap property, namely the value of any node is greater or equal than those of its left and right subtrees. The representation invariant is the following: the number of nodes in the left subtree is equal to the number of nodes in the right subtree, or exceeds it by exactly once. In the first case, we use the constructor [Same] and in the second the constructor [Diff]. Then it can be proved that [2^(h-1) <= n <= 2^h] when [n] is the number of elements and [h] the height of the tree. *) type elt = X.t type t = Empty Same of t * X.t * t (* same number of elements on both sides *) Diff of t * X.t * t (* left has [n+1] nodes and right has [n] *) let empty = Empty let rec add x = function Empty -> Same (Empty, x, Empty) (* insertion to the left *) Same (l, y, r) -> if X.compare x y > 0 then Diff (add y l, x, r) else Diff (add x l, y,r) (* insertion to the right *) Diff (l, y, r) -> if X.compare x y > 0 then Same (l, x, add y r) else Same (l,y, add x r) let maximum = function Empty -> raise EmptyHeap Same (_, x, _) Diff (_, x, _) -> x (* extracts one element on the bottom level of the tree, while maintaining the representation invariant *) let rec extract_last = function Empty -> raise EmptyHeap Same (Empty, x, Empty) -> x, Empty Same (l, x, r) -> let y,r' = extract_last r in y, Diff (l, x, r') Diff (l, x, r) -> let y,l' = extract_last l in y, Same (l', x, r) (* removes the topmost element of the tree and inserts a new element [x] *) let rec descent x = function Empty -> assert false Same (Empty, _, Empty) -> Same (Empty, x, Empty) Diff (Same (_, z, _) as l, _, Empty) -> if X.compare x z > 0 then Diff (l, x, Empty) else Diff (Same (Empty, x, Empty), z, Empty) Same (l, _, r) -> let ml = maximum l in let mr = maximum r in if X.compare x ml > 0 && X.compare x mr > 0 then Same (l, x, r) else if X.compare ml mr > 0 then Same (descent x l, ml, r) else Same (l, mr, descent x r) Diff (l, _, r) -> let ml = maximum l in let mr = maximum r in if X.compare x ml > 0 && X.compare x mr > 0 then Diff (l, x, r) else if X.compare ml mr > 0 then Diff (descent x l, ml, r) else Diff (l, mr, descent x r) let remove = function Empty -> raise EmptyHeap Same (Empty, x, Empty) -> Empty h -> let y,h' = extract_last h in descent y h' let rec iter f = function Empty -> () Same (l, x, r) Diff (l, x, r) -> iter f l; f x; iter f r let rec fold f h x0 = match h with Empty -> x0 Same (l, x, r) Diff (l, x, r) -> fold f l (fold f r (f x x0)) end
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